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How Do Heat Disp Quirks Work?


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#1 LuxAstrum

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Posted 19 April 2016 - 09:58 AM

Simple math for simple minds like mine.

lets say we have a 10% heat gen quirk, and a weapon does 10 heat, upon firing we only generate 9 heat because of the quirk.

But heat disp quirks? we have a 10% heat disp quirk, and a weapon that does 10 heat, upon firing we get 10 heat like normal, but dissipate it 10% faster? right?

#2 Deathlike

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Posted 19 April 2016 - 10:02 AM

IIRC, it's based off the mech's overall heat dissipation and multiplied by 1+the % bonus.

So in the case of the Lolcust, it's whatever you have for dissipation (normally XL 180's worth of heat dissipation + 3 external IS DHS), then multiplied by 1.18 (18% heat dissipation bonus) and that's your new dissipation value.

Edited by Deathlike, 19 April 2016 - 10:03 AM.


#3 Yosharian

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Posted 19 April 2016 - 11:10 AM

I'll save you the time and trouble: it's complete and utter ****. Expect the new quirk to be about 10% the strength of what the old one was in terms of actual combat effectiveness.

Edited by Yosharian, 19 April 2016 - 11:10 AM.


#4 Roadkill

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Posted 19 April 2016 - 11:13 AM

View PostLuxAstrum, on 19 April 2016 - 09:58 AM, said:

lets say we have a 10% heat gen quirk, and a weapon does 10 heat, upon firing we only generate 9 heat because of the quirk.

But heat disp quirks? we have a 10% heat disp quirk, and a weapon that does 10 heat, upon firing we get 10 heat like normal, but dissipate it 10% faster? right?

Correct, and likely based on the Mechs heat efficiency.

By which I mean that you'll have to figure out your Mech's actual dissipation and not just your heat sink count because in-engine DHS are different than external DHS.





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