Heavy Mechs would breach ice of a certain weakness, light Mechs would only breach weaker ice, and the quantity of heat being dissipated (Heat Level X Heat sinks) would affect the rate of ice weakening. Just a suggestion.
Edit: Okay, for a mental exercise, the number of foot-mounted heatsinks multiplied by the actual temperature of the Mech could represent the quantity of heat being delivered to the ice per second. For instance, a warm Mech with many heatsinks will dump a given quantity of heat energy just as quickly as a hot mech with very few heatsinks. Remember that 1 degree represents a quantity of thermal energy, and going from 3000 to 2999 degrees sheds the same amount of energy as going from 2000 to 1999, but I'll also throw in Le Chatelier's principle here and say that a 3000 degree Mech should shed 500 degrees' of heat energy faster than a 2000 degree Mech with an equal number of heatsinks would because the thermal gradient from 3000-to-ambient is stronger than the gradient from 2000-to-ambient. That's why a 3000 degree Mech would, *in reality*, dump heat energy faster than a 2000 degree Mech with an equal number of heatsinks would, and that explains why heat shedding is a function of heatsinks multiplied by a [mildly exponential] factor representing how much hotter you are than the ambient battlefield temperature.
Just like canon says, a hot laser-boat loaded up with double heatsinks should melt its way through the surface of a frozen lake very quickly.
Edited by Prosperity Park, 30 November 2011 - 09:46 AM.