Quicksilver Kalasa, on 26 July 2017 - 04:17 PM, said:
Here's some simple math to prove it:
For a mech with 50% heat efficiency, we get the following:
- 4% Heat gen = 2 dissipation and 3.84 (4 originally) heat generated which translates to 52.08333% heat efficiency
- 6% Cool run = 2.12 dissipation (2 originally) and 4 heat generated which translates to 53% heat efficiency
- ~1.76% improvement of cool run over heat gen quirks
- 4% Heat gen = 4 dissipation and 7.68 (8 originally) heat generated which translates to 52.08333% heat efficiency
- 6% Cool run = 4.24 dissipation (4 originally) and 8 heat generated which translates to 53% heat efficiency
- ~1.76% improvement of cool run over heat gen quirks
- 4% Heat gen = 2 dissipation and 5.76 (6 originally) heat generated which translates to 34.7222% heat efficiency
- 6% Cool run = 2.12 dissipation (2 originally) and 6 heat generated which translates to 35.333% heat efficiency
- ~1.76% improvement of cool run over heat gen quirks
i agree on your math by using heat eff to compare heat gen vs cool run and that 10% heat gen always has better heat eff. then 10% cool run. having 1 heatsink or 10000 heatsink will not change this.
My question is how did you get the 1.76% improvement?
Goodluck trying to convince the people who misunderstand the game mechanic though.
I simply take both nodes most time anyway since most my mech are hot mechs (low heat eff.)
But if i had to choose i would take heat gen even though they cost more SP i would have take those other node either way while on he other tree i would never have taken them if cool run wasnt in that tree.
Edited by Palfatreos, 26 July 2017 - 05:13 PM.